600=5x^2+22x

Solution for 600=5x^2+22x equation:

600=5x^2+22x

We move all terms to the left:

600-(5x^2+22x)=0

We get rid of parentheses

-5x^2-22x+600=0

a = -5; b = -22; c = +600;
Δ = b2-4ac
Δ = -222-4·(-5)·600
Δ = 12484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12484}=\sqrt{4*3121}=\sqrt{4}*\sqrt{3121}=2\sqrt{3121}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{3121}}{2*-5}=\frac{22-2\sqrt{3121}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{3121}}{2*-5}=\frac{22+2\sqrt{3121}}{-10}
$